Class 10 · Maths

Pair of Linear Equations in Two Variables

Two linear equations in the same two variables form a pair of linear equations. This chapter covers solving such pairs graphically and algebraically — by substitution and elimination — and deciding when a pair is consistent, inconsistent or dependent.

Solutions

Exercise 3.1

Q1. Exercise 3.1 — Question 1

Five pencils and seven pens together cost ₹250, while seven pencils and five pens cost ₹230. Form a pair of linear equations for this situation.

Let the cost of one pencil be ₹x and the cost of one pen be ₹y. From the first statement: 5 pencils and 7 pens cost ₹250 5x + 7y = 250 … (i) From the second statement: 7 pencils and 5 pens cost ₹230 7x + 5y = 230 … (ii) Equations (i) and (ii) together form the required pair of linear equations in two variables.

Final Answer: 5x + 7y = 250 and 7x + 5y = 230, where x = cost of a pencil and y = cost of a pen.

Common Mistake: Mixing up which quantity goes with which price and swapping the coefficients.

Exam Tip: Define the variables in words first — forming the equations then becomes mechanical.

Exercise 3.2

Q1. Exercise 3.2 — Question 1

Solve 2x + y = 8 and x − y = 1 by the elimination method, and state what kind of solution it is.

2x + y = 8 … (i) x − y = 1 … (ii) The coefficients of y are +1 and −1, so adding the two equations eliminates y: (2x + y) + (x − y) = 8 + 1 3x = 9 x = 3 Substitute x = 3 into (ii): 3 − y = 1 ⇒ y = 2. Since we obtained exactly one value for x and one for y, the lines intersect at a single point.

Formula: Unique solution when a₁/a₂ ≠ b₁/b₂

Final Answer: x = 3, y = 2 — a unique solution (the equations are consistent).

Common Mistake: Adding the equations when the coefficients are the same sign — that does not eliminate the variable.

Exam Tip: Always substitute your answer back into the other equation to check before writing the final line.

Exercise 3.3

Q1. Exercise 3.3 — Question 1

By comparing ratios of coefficients, decide whether the pair 3x + 2y = 5 and 6x + 4y = 9 has a solution.

Write both equations in the form ax + by + c = 0: 3x + 2y − 5 = 0 and 6x + 4y − 9 = 0 So a₁ = 3, b₁ = 2, c₁ = −5 and a₂ = 6, b₂ = 4, c₂ = −9. Now compare: a₁/a₂ = 3/6 = 1/2 b₁/b₂ = 2/4 = 1/2 c₁/c₂ = −5/−9 = 5/9 Here a₁/a₂ = b₁/b₂ but this is not equal to c₁/c₂. This is the condition for parallel lines, which never meet.

Formula: a₁/a₂ = b₁/b₂ ≠ c₁/c₂ ⇒ no solution (parallel, inconsistent)

Final Answer: No solution — the lines are parallel, so the pair is inconsistent.

Common Mistake: Forgetting to move the constant to the left side, which gives the wrong sign for c.

Exam Tip: Write all three ratios in lowest terms before comparing them.

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